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edited: last one didn't load divison signs 2NH3 mass = 17*2 = 34 g 3H2 mass = 6 g 11.2 liters H2 = 11.2/22.4 = 0.5 mole = 0.5 * 2 = 1 g 34/x = 6/1 X = 5.667 5.7 grams NH3 is required for 11.2 liters H2.
2NH3 mass = 17*2 = 34 g 3H2 mass = 6 g 11.2 liters H2 = 11.2/22.4 = 0.5 mole = 0.5 * 2 = 1 g 34 x = 6 1 x = 5.667 5.7 grams NH3 is required for 11.2 liters H2.
