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helli
Answers (1)
Given Volume: $V = x \, (3x) \, y V = 3x^2 \, y$ 0=3x2y′+6xy 0=3x2y′+6xy y′=−2y/x y′=−2y/x Total Area: AT=2(3x2)+2(3xy)+2(xy) AT=2(3x2)+2(3xy)+2(xy) AT=6x2+8xy AT=6x2+8xy dAT/dx=12x+8(xy′+y)=0 dAT/dx=12x+8(xy′+y)=0 12x+8[x(−2y/x)+y]=0
