haidy

This page lists questions and answers that were posted by visitors named haidy.

Questions

The following questions were asked by visitors named haidy.

Answers

The following answers were posted by visitors named haidy.

Δy = v0t + ½ at2 - 0.8 = (0)t + ½ (-9.8)t2 0.404 s = t Δx = v0t + ½ at2 1.2 = v0 (0.404) + ½ (0)(0.404)2 2.97 m/s = v0 (after the collision as the block leaves the table) p0 = p1 (0. 012 kg )v + (3 kg)(0 m/s) = (0.012 kg)(2.97 m/s) + (3 kg)(2.97 m/s) (0....