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gurbz
Answers (1)
You're right Adam, just plug -1.25 to find X3. So...you know... y=x^3+x+3 y'=3x^2+1 Xn=-1 The equation you use is: Xn+1 = Xn- (f(Xn)/f'(Xn)) So for: X2=(-1)- ( ((-1)^3+(-1)+3)/ (3(-1)^2+1)) X2= (-1)- (1/4) X2= -1.25 Then... X3=(-1.25)- (