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gothic vampire
Answers (25)
3c1*2c1*2c1=12
for 1 unit change in the independent variable,the dependent varriable increases by 1.44 times
20% of 1.2T= ((1.2T)+(1.2T*20T/100)) 1.44T
Is it compulsory to wear all 3 outfits?
Similarly you can find for machine B
Apply Bay's rule here A-p(E4/D)=)0.05*0.13/(0.23*0.11)+(0.45*0.2)+(0.19*0.07)+(0.13*0.05) =5/196
there are 490 perfect bottles a- (490/500)*(10/499)*(9/498) b-(10/500)*(490/499)*(9/498) c-(10/500*490/499*489/498)+(490/500*10/499*489/498)+(490/500*10/499*489/498)
This is circular permutation 5 boys can stand in a circle in (5-1)!=4! ways there are 5 gaps in between 5 boys and 5 girls can stand in those gaps in 5! ways so total number of arrangements=4!*5!=24*120=2880
p(x)-probability of x is missing for standard deviation(sigma),we need mean (mu)
write the vector pq as q-p= -2i+j+i-8j= -i-7j 3pq= -3i-21j magnitude = square root of(9+441)=15*square root of 2 componentform -3/15*square root of 2i -21/15*square root of 2j
apply (a+b)^2=a^2+b^2+2ab
what is the answer @ lily? it should be 6 hours
% error formula change in number/original number*100 =224-200/200*100=12% am I right??
reiny,the first digit can also be 3..read the question again
oops,I made a mistake 6n^2+3n=0 => 3n(2n+1)=0 =>n= 0 and n= -1/2
very simple lily x> -15 => x+15>0
Did you understand harley?
n. 9n=3(nP2) =>9n^2=3(n!/(n-2)!) =>9n^2=3(n*(n-1)(n-2)!/(n-2)!) =>9n^2=3(n*(n-1)) =>9n^2=3(n^2-n) =>9n^2=3n^2-3n =>6n^2-3n=0 =>3n(n-2)=0 =>n=0 and n=2
-3 -5 -2 -4 -1 -3 0 -2 1 -1 this is the table All numbers in input and output are in ascending order
one student's position is fixed .now the remaining 8 students can give their presentations in 8! ways 8!=8*7*6*5*4*3*2*1=40320
2 points make a straight line so no of lines required=17C2=136
15*3=5*A so A=5
hello emily,remember the properties of modulus |4x + 3| = 9 + 2x case1 4x+3=9+2x =>x=3 case2 -4x-3=9+2x =>x= -2
N is inversely proportional to A so N*A=constant N*A=3*15=45 if A becomes 5,N will be 45/5=9
solve by cross multiplication x=14*4/16=56/16=3.5
