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Questions (1)
Am i right?
answer:-x^2-2 (2x^2-3)-(3x-1)=-x^2-2
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Answers (6)
in the original problem i just raise all the numbers with powers which got me 8z+9=64z+1
Oops...I messed up....
Raise 8 to the power of 2 8z+9=64z+1 Subtract 64z from both sides of the equation which gives us: 8z+9−64z=1 Subtract 64z from 8z which gives us. −56z+9=1 Move all terms not containing z to the right side of the equation(we subtracted 9): −56z=−8
Thank you!
or is it this:2x^2-3x-2