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exib
Answers (3)
Sorry I missed a ')' dy/dx = [1/x - (1+ln(x))]/ x^2
is that e to the power of x(4-x)/6 ? If so then, dy/dx = e^[x(4-x)/6] * (2-x)/3 I hope that's right
dy/dx = [1/x - (1+ln(x)]/ x^2
