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enigma
Questions (9)
A function is given by,
f(x,y) = x^4 - y^2 - 2x^2 + 2y - 7 Using the second derivative test for functions of two variables,
3 answers
420 views
A function of two variables is given by,
f (x,y) = 4x^3 + 7xy^4 - 5y^2 + 8 Determine, fxx + fyx at x = 4.25 and y = 3.69, giving
2 answers
413 views
A function of two variables is given by,
f(x,y) = e^2x-3y Find the tangent approximation to f(0.989,1.166) near (0,0), giving
0 answers
310 views
A function of three variables is given by,
f (x,y,t) = x3y2sin t + 4x2t + 5yt2 + 4xycos t Find ft (3.44,0.58,8.1) giving your
0 answers
305 views
An initial-value problem is given by the differential equation,
f(x,y) = x + y, y(0) = 1.64 The Euler-midpoint method is used to
2 answers
665 views
Consider the initial value problem,
f(x,y) = y(18.06 - y), y(0) = 12. The exact solution of the problem increases from y(0) =12
0 answers
481 views
An initial-value problem is given by the differential equation,
f(x,y)=x(1-y^2), y(1)=0.07 Use the Euler-trapezoidal method with
0 answers
474 views
An initial-value problem is given by the differential equation,
f(x,y)=-20xy^2, y(1)=1. Use the classical fourth-order
0 answers
818 views
A function is given by, f(x)=e^-3x
write down the third-order Taylor approximation for f(x) about x =0. Hence, evaluate f(0.258)
2 answers
407 views
Answers (6)
after re-calculating the euler-midpoint method. the value I got was 1.8172 while using normal euler method is 1.968. however, I can't seem to find the exact solution to minus off the 1.8172 value to get the global error.
after calculating the y' and y'' values. the values come up be 2.7731947639 which when rounded to 5 decimal places gives the answer as: 2.773195
(-1,1) is classified as a saddle point because the value it gives after the second derivative test is less than 0 therefore the value is inconclusive. While (0,1) is classified as a local maximum because the value it gives after the second derivative test
i was going around in circles and putting the wrong values. thank you for your help. thanks.
thanks for helping me. i was stuck trying to solve this.
i apologise if that is the case. it's just that i have no idea where to start. thank you for your time.