Ask a New Question
Search
Questions and answers by
engr. josh valerio
Answers (1)
eq. 1 - - - > (y^2)=8x - - - > x=(y^2)/8 eq. 2 - - - -> point distance formula d=[(x2-x1)^2+(y2-y1)^2] ^1/2 input (4,2) and eq. 1 to eq. 2 d=[((y^2)/8 - 4)^2 + (y - 2)^2] ^1/2 differentiate d let u = ((y^2)/8 - 4)^2 + (y - 2)^2 du = 2((y^2)/8 - 4)^(2-1)
