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engmath
Questions (4)
A car traveling on a flat (unbanked) circular track accelerates uniformly from rest with a tangential acceleration of 1.70
6 answers
3,002 views
What is 14.586 Newtons converted to convert μN?? I thought it was 14,580,000 μN but I am not sure. Thank You
2 answers
427 views
The vector position of a 3.65 g particle moving in the xy plane varies in time according to the following equation.
r1 =
0 answers
1,299 views
Find f'(c) if f(x)=-3e^(x+2)+ e^(-5)
[NOTE:A small algebraic manipulation is needed first to get f(x) into a form so that the
2 answers
1,118 views
Answers (16)
and that answer comes up as incorrect...
α=a/r the time it takes to travel π/2 radians is related by π/2=.5*a*t^2/r solve for t t=sqrt(π*r/a) ω=α*t Plug in t and a/r ω=sqrt(a*π/r) The force is m*ω^2*r F=m*a*π friction is m*g*µs then m*g*µs=m*a*π so basically.... µs=a*π/g
270 just to check 270/30= 9 which is 3*3
-2.1*3.2+4.3*(-1.5) (1)First perform any calculations inside parentheses. (2)Next perform all multiplications and divisions, working from left to right. (3)Lastly, perform all additions and subtractions, working from left to right. So: first multiply terms
then its -13.17 understand why?
-11.65 if the first part of the problem is simply: -2-1*(3.2) and not (-2-1)*(3.2)as I have shown above
order of operations: (1)DO operations inside parentheses (2)Distribute powers (3)Multiply and Divide left to right (4)Add and Subtract left to right so: (-2-1)*(3.2)+4.3*(-1.5) do operations inside parentheses first (-3)*(3.2)+4.3*(-1.5) then do
1)She is not. *change be to is, change no to not
Your Welcome =D Speed is the absolute value of velocity. Velocity can be negative where as speed cannot. That is the only major difference but other than that they are the same!
yes correct!
I will do the first two for you and you can try the other three: 1) We are in the library. *change be to are 2) She is at the college? * change be to is
yes you are correct.... I wrote the formula wrong x/t instead of v/t where x(position) is the dependent variable(y) and t is the independent variable(x) sorry I know its confusing!! some people use s variable to represent the position so: delta s/delta t
velocity is the derivative of the position function or the slope of the line....So Choose two points on the graph. Subtract the "x-coordinates" (change in position), subtract the "t-coordinates" (change in time) and divide the first by the second, v/t is
after you ln both sides you end up with -3(x+2)=-5 -3x-6=-5 f(x)= -3x-1 f'(x)= -3 unfortunately that was not correct either, but I appreciate your help! :)
ah sorry... I was looking at your problem and thinking of something else. Here is the correct solution for part a so therefore... SO if F(x)=2x+3 plug it into your rational function r(x)=[f(x-h)-f(x)]/h =[2(x-h)+3-(2x+3)]/h =[2x-2h+3-2x-3]/h --->then
the rational function is r(x)=[f(x-h)-f(x)]/h (also known as the limit definition) so if your function is F(x)=2x+3 plug it into the rational function [2(x-h)+3-(2x+3)]/h =[2x+2hx-3-2x-3]/h --->then simplify =2h/h--->cancel the h's =2 then do the same
