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em0chique
Answers (19)
what is the question?? u want to know what 90x5450 is? 490500
5(3x-4)+2 15x-20+2 15x-18
x^3 +40/y -(10+3) 4^3 + 40/8 - 13 64+5-13 56
a. 2pir^2 +2pirh = 2pi(4.5^2)+ 2pi(4.5)(5) = 127.23+141.37 = 268.6cm^2 b. pir^2h = pi(4.5^2)(5) = 318.09cm^3 c. the capacity and volume are the same thing: 318.09 cubic cm
V = πr^2h = pi(21^2)(25.5) =35328.78
by 4
First find the area before and after 5*7 =35 8*10=80 then: (80/35)*100=228.57% Ans= 228.57% u can double check that ur answer is correct by simply by multiplying (228.57/100)*35 u should get 80
if u want degrees why are ur answers in percentage?? the answer is d.223 u multiply .62*360 since there's 360 degrees in a circle
Are u missing info in this question??
a. 5^3/2
Putting parenthesis would have been great (64/8)*3 + (25/5)*8 8*3 + 5*8 24 + 40 64
answer is b. 20
bc=24 this is a triple 10,24, 26 So this is a triangle so: a= 1/2bh a= (.5)*(10)*(26)
The answer is c.12
Part A a = 4*pi*r^2 = 4*pi*56^2 answer will be in mm^2 Part B v= (4/3)*pi*r^3 = (4/3)*pi*(56^3) answer will be in mm^3
a= 1/3*b^2*h
i think u wrote it incorrectly did u mean x+y= 9?? if so x +y= 9 2x-y=-3 3x = 6 x = 2 or x +y= 9 (-2) -2x-2y=-18 2x-y=-3 2x- y=-3 -3y=-21 y=7 u can use the elimination process to solve for both or u can solve for one and plug it in any one of the equations
v = (1/3)pi(r^2)h r = d/2 = 6.8/2 = 3.4 v = (1/3)pi(3.4^2)(2.8)
a) The horizontal component of the launch speed (Vo) is Vo cos = 0.6018 V. It travels 24 m horizontally in 2.20 s. Therefore X= X_0+V_x0(t) 24= 0+V_x(2.2) 10.91= V_0cos53 V_0= 18.13 b)to solve for the height after t = 2.2s y = (Vo sin 53)* t - (1/2) g t^2
