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How do you calculate the quantity in mol and grams of the reactants, when given the mass in mL of the product?

he had $30 notebook: 1/5 of $30= $6 30-6=$24 haircut: 24/2=$12 lunch: 12-10=$2

I tried calculating and did 1) mass of C8H8O3: 1.184g/mL x 5.0 mL = 5.92 g. 2) moles of C8H8O3: 5.92g x 1mol/152g = 0.0389 mol 3) ratio of reactants and C8H8O3 is 1:1:1 so they all have the same # of moles 4) mass of C7H6O3: 0.0389 mol x 138g/1mol = 5.368...