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durkasri
Answers (1)
Third term a+2d is 5 7th. Term a+6d is 13 By solving using elimination method, -4d= 8 d=-2 Substitute d value to third term a-4 = 5 a= 9 Therefore 30th term is a + 29d = 9+29(-2) = 9-58 = -49
