denisa

find the area of the region between the curve y = 3-x^2 and the line y = -1 by integrating with respect to y you first have to solve for x x=(3-y)^(1/2) then area ⌠ (3-y)^(1/2 dy from -1 to 3 ⌡ =-2/3 (3-y)^(3/2 | from -1 to 3 = -2/3(0 - 8) = 16/3 but this...