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damiensandowz
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The airborne time will be given by: t = v1/g where t is the time taken, v1 is the initial velocity and g is the acceleration due to the gravity pulling the golf ball towards the center of the earth. t=60/9.8 t=6.12244897959 seconds. Multiplying that by 2
Sporophyte, spores, gametophyte, gametes. Or gametophyte, gametes, sporophytes, spores. It depends on how we look at the life cycle of plants i.e. whether we want to start from a zygote or from a spore. Some plants (fern, for example) have alternation of
e = ten to the power of, rather.
3.25e-22 * 8000 = 2.6e-18 = 2.6*10^-18 e = to the power of.
x+y=32 x-2=y x+x-2=32 2x-2=32 2x=34 x=17 Ram is 17 years old and Shyam is 15.
5/4 cup of flour makes 10 cookies. (5/4)*5 cup of flour makes 50 cookies. = 25/4 OR 6 1/4 OR 6.25 cups. Since he already has 4 cups, he needs 2.25 more cops to finish baking.
He bought x 50-cent stamps. He bought x+20 19-cent stamps. He bought 2(x+20) 32-cent stamps. 50*x + 19(x+20) + 32*2(x+20)=3256 x=12 x+20 = 12+20=32 19-cent stamps. 2(x+20)=2*32=64 So he bought 12 50-cent stamps, 32 19-cent stamps and 64 32-cent stamps.
Make a straight line AB then construct an angle of 120 degrees at point B. Cut off an arc equal to 10 cm on the straight line produced from the 120 degree line. You now have created line BC. Once you have an intersection point, using a compass, draw an arc
What's the question?
2x^3-x^2-12x^2+6x+26x-13=0 x^2(2x-1)-6x(2x-1)+13(2x-1)=0 (2x-1)(x2-6x+13) (2x-1)(3±2i)=0 Taking the first equation (2x-1), 2x=1 x=1/2 (x2-6x+13) cannot be factorized so x=1/2 is the answer.
16x+6.
The integers are -3, -2 and -1.
$1,125. Interest = P*T*R/100 = 1500 * 1 * 7.5/100 = 112500/100 = 1125
3 percent decrease. Let the consistent percentage be 'x.' Then, x % of 8500 = 8245 x/100*8500 = 8245 x/100 = 97/100 x = 97% From above, we can find out that 97% of the students remained. Subtracting 97% from total, 3% left the university.
44.16 square centimeter.
The shortest side is 39 inches. Let the 3 sides be a, b, and c where a is the longest and c the shortest. By the question, c+7 = a c+2 = b From the above information, we can calculate that, a-5=b a=5+b ----- equation (i) Similarly, a+b+c=126 c=126-a-b
40 students were in the class.
54 (9-2)squared +(7-10 divided by 5) = 7^2 + (7-2) = 49 + 5 = 54 BODMAS RULE!!
y = x*9.10 inverse of the function is x = y/9.10. To calculate the no. of hours, replace y in the above equation with the money you need to afford the car. i.e. x = y/9.10 = 300 / 9.10 = 32.96 = 33 hours.
Following the BODMAS rule, brackets go first. (13-2)^2 + 14 -(12/3) = 11^2 + 14 - 4 = 11^2 + 10 = 121 + 10 = 131
Let the money you have be "x" and what your friend has be "y." In first case, x:(y+40) = 4:5 5x = 4(y+40) 5x = 4y + 160 x = (4y+160)/5 ----- equation (i) In second case, (x+40):y = 8:1 x+40 = 8y x = 9y-40 (4y+160)/5 = 8y-40 [from equation (i)] 4y+160 =
8 is not a real number, my apologies. It's not rational.
1. Irrational. 2. Irrational. 3. Rational. 4. Rational. 5. Rational. 6. Rational. 7. Rational. 8. Rational. 9. Irrational. 10. Irrational. 11. Rational.
Let A (-2,5) be (x1,y1) and B(9,5) be (x2,y2). Using distance formula, distance^2(d^2)=(x2-x1)^2+(y2-y1)^2 = [9-(-2)]^2 + [5-5]^2 = 11^2 + 0^2 = 11^2 = 121 Now, converting the above information to its square root to obtain the actual length. distance (d)=
If $6,490 is the tax for $590,000 then one dollar will cost a tax of 590,000/6,490 = 11/1000 dollars. If 1 dollar taxes 11/1000 dollars then $710,000 dollar will tax (11/1000*710000=7810 dollars.