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dais
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A sample survey interviews an SRS of 263 college women. Suppose (as is roughly true) that 75% of all college women have been on
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n=(z*/m)squared(p*)(1-p*) so be sure to square (z*/m) m= margin of error, the invNorm for 90% is 1.645, p*=.5, if not given The problem worked out: (1.645/0.02)squared(.5)(1-.5)= 1691.265625 so the sample size should be 1691 people. Hope this helps
