dais

A sample survey interviews an SRS of 263 college women. Suppose (as is roughly true) that 75% of all college women have been on a diet within the past 12 months. Using the Normal approximation, what is the probability (±0.001) that 82% or more of the wome...

n=(z*/m)squared(p*)(1-p*) so be sure to square (z*/m) m= margin of error, the invNorm for 90% is 1.645, p*=.5, if not given The problem worked out: (1.645/0.02)squared(.5)(1-.5)= 1691.265625 so the sample size should be 1691 people. Hope this helps