Questions and answers by

collabo

Answers (1)

note: pH +pOH = 14 Which becomes. 12.31 + pOH = 14, POH = 14-12.31, = 1.69. But pOH = -log[OH^-] So 1.69=-log[OH^-] 1.69=log(1/OH) Antilog(1.69)=1/OH OH=1/antilog(1.69)

Ask a New Question