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For propanoic acid HC3H5O2, Ka = 1.3 ✕ 10−5 and 0.102 M solution.
[HC3H5O2] ____M [C3H5O2− ] ____M percent dissociation
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If it helps, I have: [H+] = 0.00115 [OH-] = 8.696e-12 pH = 2.94 These are verified to be correct.
