cheerie

im a bit puzzled, please help me gain the sanity required for this confusion... suppose a ball is thrown from the top of a cliff, and i am supposed to get its final velocity; since when the ball reaches it maximum height, the vf which becomes the vi or in...

use formula vfy= viy+gt... vfy= 0, this is always true when the object reaches its maximum height. viy= vi sin degress (horizontal) viy= 120sin 60 viy= 103.92 g= -9.81 m/s2 thus: vfy= viy + gt 0= 103.92 + (-9.81)(t) t = -1o3.92/-9.81 1o.59seconds from the...

it depends... when you talk about acceleration of object going downward, its -g... when acceleration going up, example an object is thrown, i think its 0. ax=o; ay= -g

do you still need the computation for this one?.