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bridgatte
Answers (1)
agcl:kcl 1 : 1 n of agcl=(0.733g/143.32g.mol)=5.11*10^-3mol n of kcl=5.11*10^-3mol m kcl=5.11*10^-3mol(74.5513g/mol)=0.381g %kcl=(0.381/0.400)(100)=95.25%
