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bobsley plz conform
Questions (1)
if 4.55 g of sodium sulphide and 15.0 g of bismuth nitrate are dissolved in separate beakers of water which are then poured
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Answers (1)
balanced equatoin is 3Na2S + 2Bi(NO3)3 --- Bi2S3 + 6Na^+ + 6NO3^- moles of Na2S = 0.058 moles of Bi(no3)3 = 0.038 Na2S = 0.058 / 3 = 0.019 Bi(no3)3 = 0.038 / 2 = 0.019 both are same for Bi2S3 from balanced equation so the mass is 9.77 g no limiting
