blingblongyaomingde

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Sn (s) + 2Cl2(g) --> SnCl4(l) Change in enthalpy = DH1 + DH2 + DH3 Sn(s) + Cl2(g) --> Sn Cl2(l) DH1 = -186.2 kJ Sn Cl2(l) --> SnCl2(s) DH2 = ? <-- find this either in a table in your book or online SnCl2(s) + Cl2(g) --> SnCl4(l) DH3 = -325.1 kJ
12 years ago