aussi_bob

This page lists questions and answers that were posted by visitors named aussi_bob.

Questions

The following questions were asked by visitors named aussi_bob.

Answers

The following answers were posted by visitors named aussi_bob.

C in CO2 is 12/ 44 % = 27.27% in 1.35 g of CO2 there is (27.27% of 1.35) g of C = 0.3681g or 0.3681 /12 moles of C = 0.031 moles % C in the compound = .3681 / .952 = 38.67% H in H2O = 2 / 18 % = 11.111 % in .826 g of H2O we have 11.11 % of .826 = 0.09177...