aso

the average number of passengers on a subway car is 60. If the number of passengers on a car has normal distribution with a standard deviation of 20, approximately what the percent of subway cars carry more than 80 passengers?

11/6= 6*1 +1=7/6 2x/3=7/6 2x*6=7*3 x=21/12=7/4 x=3/4*3=9/4 5/6-3/4=2/3x for 5/6-3/4---> 6*4=24 then (5*4)/24-(3*6)/24=2/3x (20-18)/24=2/3x 2/24=2/3x x=1/8

59/2 / 3/4= 118/3= 39 1/3 so it made 39 and left 1/3

mm is wrong i got 1/5 :/