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asingh

Questions (3)

If f(x+y) = f(x) f(y) for all real x and y and f(0) is not equal to 0 , then the function g(x) = f(x) /[1+{f(x)}^2] isa) odd
1. 1 answer
2. 390 views
If f(x+y) = f(x) f(y) for all real x and y and f(0) is not equal to 0 , then the function g(x) = f(x) /[1+{f(x)}^2] isa) odd
1. 11 answers
2. 583 views
A nut wholesaler sells two types of mixes of cashews and peanuts. He makes a low-grade mix containing 8 pounds of peanuts and 4
1. 3 answers
2. 1,098 views

Have I done wrong ? ..because no one is answering
I have done kindly cross check please let z =f(x) then denominator is always positive. Now, Numerator z [consider f(z) = e^z. then e^(x+y) = e^x e^y then g(x) = e^x/(1+e^2x)] y = 0 f(y) is not 0, say it is -1 then f(x+0) = f(x)*-1 = -f(x) but if when y = 0
let z =f(x) then denominator is always positive. Now, Numerator z y = 0 f(y) is not 0, say it is -1 then f(x+0) = f(x)*-1 = -f(x) but if when y = 0 ,f(y) = +2 then f(x+0) = f(x)*2 [even if f(-x) = f(x) odd if f(-x) = -f(x)] therefore, answer is even
its even
Dont know its even or odd i request
i request ... because these type of questions are hardly to understand for me
can u complete it please. I have a problem in this sum

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