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Zozina
Questions (2)
Question:A fair coin is flipped independently until the first Heads is observed. Let the random variable K be the number of
3 answers
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Hi everyone. I am struggling a bit with this one example question I am doing.
Problem: There is a group of 12 people, 6 men and 6
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Answers (9)
Yes. By definition, the mode is the number that occurs most frequently in the set. Therefore it has to be in the set.
How many letters are there in the alphabet? 26 How many vowels are there in the alphabet? 5 Therefore, the probability of picking one vowel is 5/26. The probability of picking N vowels is (5/26)^N or 5/26 * 5/26 * 5/26.... (N times). So for your question,
@Help Yes that is the right answer.
Sorry, typo it should be (R+1)^2 there, not (R+1)^1
@Anonymous, E[((R+1)^1 - (R-1)^2)/100] = E[4R/100] =1/25 * E[R] = 1/25 * 3.5 = 0.14.
1) The random circle can only intersect the circle of radius 5 if the centre of the random circle is at most 1 unit away from the circumference of the circle of radius 5. So basically we can draw two boundaries above and below the circle of radius 5. These
Ok, I know my mistake, I didn't read the question carefully, but was on the right track
Oh I simply divide those two results I mentioned, but I am not sure why that works. Because can't, Anne and Billy, be placed in the committee in different ways? 10C3 / 12C5 makes it seem like the ways in which Billy and Anne can be arranged in the
Hi Scott. Hmm, I am still unsure what you mean by that. I guess the probability of choosing Anne, in particular, is 1/12, and then the probability of choosing Billy after that becomes 1/11. So maybe 1/12 * 1/11 * (10C3)/(12C5) ? I am quite confused.
