Let's factor the trinomial x² + bx + c. We know that if b²-4c >= 0 then this trinomial has zeros and it can be factorized. It's zeros are x1 = [ -b + √(b²-4c) ] / 2 and x2 = [ -b - √(b²-4c) ] / 2. So, we can factor it as x² + bx + c = (x-x1)(x-x2). In a c...
12 years ago