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Yamy

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Step 1: (0.5*9110.0 - 9110.0)/ (200.5 - 9110.0)= erf(ξ) Step 2: erf(ξ < 0.6), use the approximation erf ξ = ξ Step 3: t= d^2/4*D*ξ^2 d=88.5 x 10-2 cm D=3.091 x 10-7 cm2/s Step 4: t in sec -> hours Conversion seconds to hours is total/(60x60)
Step 1: (0.5*9110.0 - 9110.0)/ (200.5 - 9110.0)= erf(ξ) Step 2: erf(ξ < 0.6), use the approximation erf ξ = ξ Step 3: t= d^2/4*D*ξ^2 d=88.5 x 10-2 cm D=3.091 x 10-7 cm2/s Step 4: t in sec -> hours Conversion seconds to hours is total/(60x60)
Step 1: (0.5*7865 - 7865)/ (193.5 - 7865)= 0.512611614417(erf(ξ)) Step 2: erf(ξ < 0.6), use the approximation erf ξ = ξ Step 3: t= d^2/4*D*ξ^2 t=(59.0x10^-2)^2/4(3.091 x 10^-7)(0.512611614417)^2 t=0.3481/3.2488965297e-07 t=1071440.70862 d=59.0 x 10-2
How did you get the answer? or what is your answer?
5.00*10^22 / (gallium level*10^-8)
Same here, can anyone show how to insert the data into the formulas. Thank you
Could someone fill the data above into the formula, so we can get an idea how to search the answer? Thank you
I agree I) is wrong
Don't think its a correct answer!

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