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What Zit Tooya
Answers (3)
y'=-8sin(4x)cos(4x) y"=-8[sin(4x)(-sin(4x))*4+cos(4x)(cos(4x))*4] y"=-8[-4sin^2(4x)+4cos^2(4x)] y"=-32[cos^2(4x)-sin^2(4x)]
1c, 2b, 3a, 4a, 5b, 6a, 7c, 8d, 9c, 10b
Can'tSayMyName is right
