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A 56 kg rock climber is climbing a "chimney" between two rock slabs as shown in the figure. The static coefficient of friction between her shoes and the rock is 1.02; between her back and the rock it is 0.70. She has reduced her push against the rock unti...
15 years ago

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The following answers were posted by visitors named Web.

Push against the rock= (mg)\(u1+u2)
15 years ago
force of push = (mg)/(u1+u2), so (49*9.8)/(1.2+.8)=240.1N fraction of weight= (u1)/(u1+u2),so (1.2)/(1.2+.8)=.6
15 years ago
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