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Vara prasad
Answers (1)
u=60×5÷18=50÷3m/s v=15×5÷18=25÷6m/s Using v^2=u^2+2as,we get (50÷3)^2=(25÷6)^+2×a×450 a=-125÷36×12m/s^2 s1=v^2÷2a=25÷6×25×36×12÷6×2×125=30m s1 is the further distance travelled before coming to rest.
