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Questions (2)
Calculate the energy required to change the temperature of 256.7 mL of water at 22.0 degrees celsius to ice at a temperature of
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When the power supplying a 30.0 gallon water heater was turned off, the temperature dropped from 75.0 degrees celsius to 22.5
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Answers (3)
The mass of the ice should be the same as the mass of the H2O right?
Okay, thank you for clarifying. :)
I could multiply 30 by 3.785 L to find the volume, but to find the mass of water used I also need the density of the water which is not given. Is there a different equation I should be using other than... qH2O = mH2O x CsH2O x delta T ?
