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TheAopsMachinist
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That is whyy the solution is 81.
Let $r$ be the common ratio of the geometric sequence. To get from the $23^\text{rd}$ term of the sequence to the $28^\text{th}$ term, we start with the $23^{\text{rd}}$ term and multiply by $r$ five times. Therefore, we have \[16r^5 = 24,\]so $r^5 =
