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Solution: First, find the constant of variation "k", R = kst^2 Substitute: (32.4) = k (0.2)(9)^2 (32.4) = k (0.2)(81) (32.4) = k (16.2) k = 32.4/16.2 k = 2 - Constant of variation Then, find R when S=0.5 and T=5 Solution: R = kst^2 R = (2)(0.5)(5)^2 R =
Solution: suppose: cost of appliance (c), number of watts (w), hours (h) and cost per kilowatt hour (p) Math sentence: c = kwhp substitute: c = k (70)(2)(8.99) c = (1)(1258.6) c = 1256.6 Therefore the cost of operation is 1,256 pesos and 6 centavos

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