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Calculate the mass of each product formed when 43.82g of diborane (B2H6) reacts with excess water:B2H6(g) + H2O(l)--> H3BO3(s) +
1. 2 answers
2. 1,231 views
Calculate the mass of each product formed when 43.82g of diborane (B2H6) reacts with excess water:B2H6(g) + H2O(l)--> H3BO3(s) +
1. 4 answers
2. 4,490 views

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