TYLER CHIRECE

calculate the ph of resulting solution when 2.50 ml of the 2.60 M acetic acid is diluted to make a 250.0 ml solution

A solution household bleach contains 5.25% NaClO, by mass. Assuming that the density of bleach is the same as water(1.0g/ml). Calculate the volume of household bleach that should be diluted with water to make 500.0 ml of a ph= 10.26 solution. So, the firs...

Rank these elements according to first ionization energy.. I ranked them like this Ar Cl S P Si Al Mg Na but then it tells me that two elements should move up one spot in the ranking because of stable electrons configurations. Which ones would be moved up...

Oh! wait but don't i have to plug it into ka=x^2/(0.0260-x) , ka of the acetic acid is 1.8 x 10^-5 and then solve for x ?

Uh how do you convert the 5.25% to molarity?

wouldnt the answer be 500 ml? since the density of water is the same as the bleach?