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Solution Asumption α z = 26 × 1 0 − 6 / ° C α z =26×10 −6 /°C α s = 11 × 1 0 − 6 / ° C α s =11×10 −6 /°C So length of scale at 25°C 100 = l 0 ( 1 + α z Δ t ) 100=l 0 (1+α z Δt) l 0 = 99.93 c m l 0 =99.93cm So Δ
