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Answers (1)
(x)(y) ≤ 48 And x+2y=20 (20-2y)(y) ≤ 48 x=20-2y or y=(20-x)/2 choose one of the two 20y-2y^2 ≤ 48 (20-x)/2 ≥ 6 or (20-x)/2 ≤ 4 -2y^2+20y-48 ≥ 0 20-x ≥ 12 20-x ≤ 8 y^2-10y+48 ≥ 0 -x ≥ 12-20 -x ≤ 8-20 y^2-6y-4y+48 ≥ 0 x ≤ 8 x ≥ 12
