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Stefan A
Answers (1)
MW(Na2CO3)=105.96g/mol Volume- 155g H20 = 0.155L H20 Concentration- 8.20mol/L n=CV n=(8.20mol/L)(0.155L) n=52.9mol m=nMW m=(52.9mol)(105.96g/mol) m=5605.6g m=5.61Kg