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Questions (2)
Find the emf for the cell
Cr(s) |Cr3+(aq, 0.37 M) || Pb2+(aq, 0.0095 M) | Pb(s). Answer in units of V I don't know what to do
1 answer
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Find the emf for the cell
Cr(s) |Cr3+(aq, 0.37 M) || Pb2+(aq, 0.0095 M) | Pb(s). Answer in units of V I don't know what to do
10 answers
4,633 views
Answers (4)
the voltage would be 1.66 + -.13 which is 1.53V
.73 - (.05916/6)*log(2)/(2) for Cr? -.13 - (.05916/6)*log(3)/(3) for Pb?
I receive the answer: -442866.15 J or -443 kJ with significant figures
I got .6-(.0592/6)*log((.37)^2/(.0095)^3) which ends up being .558V Is that right?
