Someone PLEASE HELP!
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Questions
The following questions were asked by visitors named Someone PLEASE HELP!.
Answers
The following answers were posted by visitors named Someone PLEASE HELP!.
I got .6-(.0592/6)*log((.37)^2/(.0095)^3) which ends up being .558V Is that right?
15 years ago
I receive the answer: -442866.15 J or -443 kJ with significant figures
15 years ago
.73 - (.05916/6)*log(2)/(2) for Cr? -.13 - (.05916/6)*log(3)/(3) for Pb?
15 years ago
the voltage would be 1.66 + -.13 which is 1.53V
15 years ago