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SkiMasktheSlumpGod
Questions (4)
tanx cotx
------- + ------- = 1 +secxcscx 1 - cotx 1- tanx prove the proof
2 answers
699 views
2cos2x=-sinx
solve for x over the interval [-pi,+pi] x= 0.6349radians x=2.507radians x= 1.003 radians x= 2.138 radians
10 answers
717 views
2sec^2x - 3tanx - 5 = 0
I got x= 1.24 radians x= 4.38 radians x= -0.74 radians x= -3.88 radians
2 answers
435 views
tan4theta = (radical 3) / 3
theta = 7pi/24, 13pi/24, 19pi/24 Let me know if im right.
3 answers
545 views
Answers (5)
lol i see my mistake i divided by 8 and not -8
2 - 4sin^2 x + sinx = 0 -4sin^2x + sin x + 2 = 0 a= -4 b= 1 c= 2 why are you multiplying by -1?
so if c=2 then the values have to be x= 0.6349radians x=2.507radians x= 1.003 radians x= 2.138 radians
2cos2x=-sinx 2cos 2x + sinx = 0 2( 1 - 2sin^2 x) + sinx = 0 4sin^2 x - sinx - 2 = 0 it should put 4sin^2 x - sinx + 2 = 0
arctan(-rad3 / 3)= -pi/6 ?