SkiMasktheSlumpGod

This page lists questions and answers that were posted by visitors named SkiMasktheSlumpGod.

Questions

The following questions were asked by visitors named SkiMasktheSlumpGod.

tan4theta = (radical 3) / 3 theta = 7pi/24, 13pi/24, 19pi/24 Let me know if im right.

2sec^2x - 3tanx - 5 = 0 I got x= 1.24 radians x= 4.38 radians x= -0.74 radians x= -3.88 radians

2cos2x=-sinx solve for x over the interval [-pi,+pi] x= 0.6349radians x=2.507radians x= 1.003 radians x= 2.138 radians

tanx cotx ------- + ------- = 1 +secxcscx 1 - cotx 1- tanx prove the proof

Answers

The following answers were posted by visitors named SkiMasktheSlumpGod.

arctan(-rad3 / 3)= -pi/6 ?

2cos2x=-sinx 2cos 2x + sinx = 0 2( 1 - 2sin^2 x) + sinx = 0 4sin^2 x - sinx - 2 = 0 it should put 4sin^2 x - sinx + 2 = 0

so if c=2 then the values have to be x= 0.6349radians x=2.507radians x= 1.003 radians x= 2.138 radians

2 - 4sin^2 x + sinx = 0 -4sin^2x + sin x + 2 = 0 a= -4 b= 1 c= 2 why are you multiplying by -1?

lol i see my mistake i divided by 8 and not -8