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Simon onyango
Answers (1)
6log_2(64)^1/3+10log_3(243)^1/5 =2log_2 (64)+10log_3 (243)^1/5 =2log_2(2)^6+2log_3 (243) =2log_2(2)^6+2log_3(3)^5 =2log_2(2)^6+10log_3(3) =12log_2(2)+10log_3(3) Being that log_a(a)=1 Therefore 12(1)×10(1) =120
