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Simmi Mathuri
Answers (1)
3^x =5^y=75 ^z 3^x =5^y=(3X5^2) ^z 3^x =5^y=3^zX5^2z 3^x/(3^zX5^2z) =5^z/(3^zX5^2z) 3^(x-z)/5^2z=5^(y-z)/3^z 3^(x-z)/5^2z=3^-z/5^-(y-2z) On equating (x-z) /2z=z/(y-2z) xy-2xz-yz+2z^2=2z^2 xy-2xz-yz=0 xy-z(2x+y) =0 xy=z(2x+y) z=xy/(2x+y) hence proved
