Shraddha patel

This page lists questions and answers that were posted by visitors named Shraddha patel.

Questions

The following questions were asked by visitors named Shraddha patel.

Answers

The following answers were posted by visitors named Shraddha patel.

Taking E =118millivolt... 2H+. +2e ...H2 E= E*-0.059/2log H2/[H+]2 -118=0-0.059/2log 1/[H+]2 Solving it by using antilog we will get 0.01
6 years ago