Actually this question is two parts. The first part is to find the Final Molarity which is (3.6 g * 1 mole /143.35 g) / (32.55 ml * 1 L /1000 ml) = 0.77 mol/L or M The second part is to find how many millilitres of AgNo3 which has 1.85 M. I don't understa...
12 years ago