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Shoba
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If your solution’s final volume of 32.55 mL yields 3.6 grams of AgCl, determine the Molarity of the final solution. Also, how
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If your solution’s final volume of 32.55 mL yields 3.6 grams of AgCl, determine the Molarity of the final solution. Also, how
2 answers
916 views
Answers (1)
Actually this question is two parts. The first part is to find the Final Molarity which is (3.6 g * 1 mole /143.35 g) / (32.55 ml * 1 L /1000 ml) = 0.77 mol/L or M The second part is to find how many millilitres of AgNo3 which has 1.85 M. I don't
