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Sheraz
Answers (1)
P[C.S]=270/500 P[Maths]=345/500 P[C.S ∩ Maths]=175/500 ( P[C.S U Maths] )' = ? ANS. ( P[C.S U Maths] )' = 1-P[C.S U Maths] =1-{P[C.S] + P[Maths] - P[C.S ∩ Maths]} =1-{270/500 + 345/500 -175/500 } =1-{440/500} =1-0.88 =0.12
