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Shahiahi
Answers (2)
Change all the temp. to Kelvin first. Ice is 0C in solid form so there is a latent heat too. 4187(190/1000)(352-T)=333x1000x11/1000 + 4187(11/1000)(T-273) Solve for T? Then (T-273) is in Celsius. Difference = 79 - (T-273)
Heat releasing from coffee (water in this case) is equal to the heat gain for ice melting to water at 0 deg plus water to raise for the final temp.
