Answers by visitors named: Shabnam P A

Change in K E = work done 1/2m(v2^2-v1^2) =FS Here v1 is the initial velocity and v2 ia the final velocity V1=√2gh= √2×9.8×50=31.3 m/s( dropped from cliff) V2=P*x= 0×1=0(pentration velocity) 1/2*(40/9.8)*(0-31.3^2) =mgx-Px -1999. 36=40*9.8*1-P*1 P=2039.88 N