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Sehra
Answers (1)
first, sub in both x values first (x-2), x=2 f(2) = (2)^3 + 4(2)^2 + k(2) - 4 f(2) = 20 + 2k same with (x+2), x= -2 f(-2) = (-2)^3 + 4(-2)^2 + k(-2) - 4 f(-2) = 4 - 2k we know that f(2) (x - 2) remainder is 2 times larger than f(-2) (x + 2) remainder, so:
