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Sarskia
Questions (1)
The curved section can be modelled by the parabola
y=3x-3/4x^2 Use calculus to find the maximum height of the curved parabolic
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Answers (3)
I had a run over it myself and got the maxima as (-2,-3) same numbers, but negative form?
Okay, thank you very much!
..The last one. Confirm by Calculus: f(x)=3x-3/4x^2 f'(x)=3-(3/2)x At the vertex, f'(x)=0 x=3*(2/3)=2 y=3(2)-(3/4)(2²) =6-3 =3 So the vertex is at (2,3) A question regarding the first step (differentiation) How do you differentiate the fractions? I'm
